Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 4 - Congruent Triangles - Algebra Review - Page 257: 1


The solution is $(-3, -7)$.

Work Step by Step

We can use the first equation to substitute for $y$ in the second equation. Then we can solve for $x$ first: $x - 4 = 3x + 2$ Move the $x$ terms to the left side of the equation by subtracting $3x$ from each side of the equation: $-2x - 4 = 2$ Move constants to the right side of the equation: $-2x = 6$ Divide each side of the equation by $-2$ to solve for $x$: $x = -3$ Now that we have the value for $x$, let's plug this value for $x$ into the first equation: $y = -3 - 4$ Subtract to solve for $y$: $y = -7$ The solution is $(-3, -7)$.
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