Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 12 - Circles - 12-2 Chords and Arcs - Practice and Problem-Solving Exercises - Page 777: 17

Answer

$ d=6 \ in.$

Work Step by Step

Let us consider that $d$ is the distance of the cross-section from the center of the circle. Apply Pythagorean Theorem. $d^2+8^2=(10)^2 \\ d^2+64=100 \\ d^2=36$ Therefore, $ d=6 \ in.$
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