Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 12 - Circles - 12-2 Chords and Arcs - Practice and Problem-Solving Exercises - Page 777: 16

Answer

$ r=12 \ cm$

Work Step by Step

Let us consider the radius of A $r(cm)$ . Apply Pythagorean Theorem. $r^2+5^2=(13)^2 \\ r^2+25=169 \\ r^2=144 \\ r=\sqrt {144} \ cm$ Therefore, $ r=12 \ cm$
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