Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 11 - Surface Area and Volume - 11-6 Surface Areas and Volumes of Spheres - Practice and Problem-Solving Exercises: 16

Answer

$154$ $in.^{2}$

Work Step by Step

We first solve for the radius: $\frac{22}{\pi}$= diameter $\frac{22}{\pi}\div2$= radius We use the equation for the surface area of a sphere to obtain: $SA= 4\pi r^{2}$ $4\pi(\frac{22}{\pi}\div2)^{2}= 154$
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