## Geometry: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 11 - Surface Area and Volume - 11-6 Surface Areas and Volumes of Spheres - Practice and Problem-Solving Exercises: 13

#### Answer

$62$ $cm^{2}$

#### Work Step by Step

We first solve for the radius using the diameter: $\frac{14}{\pi}$= diameter $\frac{14}{\pi}\div2$= radius We use the equation for the surface area of a sphere to obtain: $SA= 4\pi r^{2}$ $4\pi(\frac{14}{\pi}\div2)^{2}= 62$

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