Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 11 - Surface Area and Volume - 11-5 Volumes of Pyramids and Cones - Practice and Problem-Solving Exercises - Page 730: 17

Answer

$\frac{16}{3}\pi ft^{3}\approx 17 ft^{3}$

Work Step by Step

We use the equation for the volume of a cone to solve: Volume of a cone = $\frac{1}{3}\times \pi \times radius^{2} \times height$ V = $\frac{1}{3}\times \pi \times 2^{2} \times 4$ V = $\frac{1}{3}\times \pi \times 4 \times 4$ V = $\frac{1}{3}\times16\pi$ V = $\frac{16}{3}\pi$ $\frac{16}{3}\pi ft^{3}\approx 17 ft^{3}$
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