Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 11 - Surface Area and Volume - 11-5 Volumes of Pyramids and Cones - Practice and Problem-Solving Exercises - Page 730: 13


3714.5 mm cubed

Work Step by Step

Use the Pythagorean theorem to find height of the pyramid: $24^{2} - 11.5^{2} = h^{2}$ $443.75= h^{2}$ $\sqrt 443.75 = h^{2}$ Volume of a square pyramid = $\frac{1}{3}\times base \times height$ $V = \frac{1}{3} \times 23\times 23 \times \sqrt 443.75$ V = 3714.5 mm cubed
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