Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-8 Geometric Probability - Lesson Check - Page 671: 4

Answer

$\dfrac{3}{7}$ or, $42.9 \%$

Work Step by Step

The probability that the point $T$ lies on the segment $\overline{BC}$ can be computed as: $P(T \in \overline{BC})=\dfrac{BC}{AD}$ Where, $BD=9-6=3$ and $AD=10-3=7$ Now, $P(T \in \overline{BC})=\dfrac{BC}{AD}=\dfrac{3}{7}$ or, $42.9 \%$
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