Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-8 Geometric Probability - Lesson Check - Page 671: 3

Answer

$\dfrac{4}{7}$ or, $57.1 \%$

Work Step by Step

The probability that the point $T$ lies on the segment $\overline{BD}$ can be computed as: $P(T \in \overline{BD})=\dfrac{BD}{AD}$ Where, $BD=10-6=4$ and $AD=10-3=7$ Now, $P(T \in \overline{AB})=\dfrac{BD}{AD}=\dfrac{4}{7}$ or, $57.1 \%$
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