Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-6 Circles and Arcs - Practice and Problem-Solving Exercises - Page 656: 55

Answer

$7.9 \ units$

Work Step by Step

Let $C$ be the circumference of a circle: $C=2 \pi r$ or, $C=\pi d~~~~(1)$ Here, $r$ represents radius and $d$ is diameter. The endpoints of the semi-circle correspond to the endpoints of its diameter. We use the distance formula to find: $d=\sqrt{(4-1)^2+(7-3)^2}=\sqrt{25}=5$ Thus, equation (1) becomes: $L=\dfrac{1}{2} \pi d=\dfrac{1}{2} \times \pi (5) \approx 7.9 \ units$
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