Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-6 Circles and Arcs - Practice and Problem-Solving Exercises - Page 656: 49

Answer

$31 \ m $

Work Step by Step

$l=\dfrac{\text{Measure of the arc}}{360^{\circ}} \times 2 \pi r ~~~(a)$ or, $l=\dfrac{\text{Measure of the arc}}{360^{\circ}} \times \pi d~~(b)$ Here, $r$ represents radius and $d$ is diameter. The total length $L$ is given by: $L=2(L_{inner}+L_{outer})$ So, we have $L=2[\dfrac{\text{90}}{360^{\circ}} \times 2 \pi (4)+\dfrac{\text{90}}{360^{\circ}} \times 2 \pi (6)]\\=2(2\pi+3)\\=(5\pi)(2)\\ \approx 31 \ m $
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