Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-4 Perimeters and Areas of Similar Figures - Lesson Check: 4

Answer

$\sqrt 6$:4

Work Step by Step

Use $a^{2}$:$b^{2}$ for the ratio of the areas. $\frac{48}{128}$ Simply $\frac{48}{128}$=$\frac{6}{16}$ The ratio of the areas is the square of the ratio of the perimeter. Therefore, take the positive square root of each to find the ratio of their perimeters. $\frac{\sqrt 6}{\sqrt 16}$=$\frac{\sqrt 6}{4}$ The ratio can be written as $\frac{\sqrt 6}{4}$ or $\sqrt 6$:4
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.