Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-4 Perimeters and Areas of Similar Figures - Lesson Check - Page 638: 3

Answer

69.3 $ft^{2}$

Work Step by Step

Create a proportion by using the ratios of the areas. In problem 2, you found the ratio of the areas to be equal to 16:9. $\frac{16}{9}$=$\frac{A}{39}$ Cross multiply. 9A=16(39) 9A=624 Divide both sides by 9 A=69.4
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