Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.2 - Pyramids, Area, and Volume - Exercises - Page 422: 25

Answer

T$\approx$116.5 in$^2$

Work Step by Step

B=x$^2$ 72=$\frac{1}{3}$Bh 72=$\frac{x^3}{3}$ x$^3$=216 x=6 T=36+(.5)(4)(6)($\sqrt 45$) T=36+12$\sqrt 45$ T$\approx$116.5 in$^2$
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