Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.2 - Pyramids, Area, and Volume - Exercises: 20a

Answer

111

Work Step by Step

We find the height of each triangle on the side: $ h = \sqrt{8^2 - 3^2} = \sqrt{55}$ There are 5 sides of length 6, so: $A = 1/2(6)(5)( \sqrt{55}) = 15 \sqrt{55} = 111$
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