Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.3 - Regular Polygons and Area - Exercises - Page 378: 28

Answer

1080 $ft^{2}$

Work Step by Step

Given in a regular octagon the approximate ratio of the length of an apothem to the length of a side is 6:5 For a regular octagon with a side of length 15 ft The area of a regular polygon whose apothem has length a and whose perimeter P is given by A = $\frac{1}{2}$ ap Lets take the ratio of apothem and side ratio 6:5. By proportionality constant x The apothem a = 6x side s= 5x But given side of length = 15 ft s = 5x = 15ft x = $\frac{15}{5}$ = 3 ft apothem of octagon a = 6x = 6* 3ft= 18 ft The perimeter of octaon P = 8s = 8 * 15 = 120 ft The area of octagon A = $\frac{1}{2}$ ap = $\frac{1}{2}$ *18 * 120 = 1080 $ft^{2}$
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