Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.3 - Regular Polygons and Area - Exercises - Page 378: 27

Answer

460.8$ft^{2}$

Work Step by Step

Given in a regular dodecagon the approximate ratio of the length of an apothem to the length of a side is 15:8 The length of the apothem = 12ft The area of a regular polygon whose apothem has length a and whose perimeter P is given by A = $\frac{1}{2}$ ap Lets take the ratio of apothem and side ratio 15:8. By proportionality constant x The apothem a = 15x side s= 8x But given apothem of length= 12 ft a = 15x = 12ft x = $\frac{12}{15}$ = 0.8 ft side of dodecagon s = 8x = 8 * 0.8 ft= 6.4 ft The perimeter of dodecagon P = 12s = 12 * 6.4 ft = 76.8 ft The area of octagon A = $\frac{1}{2}$ ap = $\frac{1}{2}$ *12 * 76.8 = 460.8$ft^{2}$
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