Answer
Using theorem 6.3.7, we obtain that $AB \times AC = AF^2$ and $AD \times AE = AF^2$. Using substitution, we obtain: $AC \times AB = AE \times AD$
Elementary Geometry for College Students (5th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
1439047901
ISBN 13:
978-1-43904-790-3
Chapter 6 - Section 6.3 - Line and Segment Relationships in the Circle - Exercises - Page 307: 27
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