Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 6 - Section 6.3 - Line and Segment Relationships in the Circle - Exercises - Page 307: 17

Answer

DE=9$\frac{2}{5}$ = 9.4

Work Step by Step

AC(AB)=AE(AD) 14(6)=15(AD) AD=$\frac{14(6)}{15}$ AD=$\frac{28}{5}$ We must find DE DE = 15- $\frac{28}{5}$ DE = $\frac{47}{5}$ DE= 9.4
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