## Elementary Geometry for College Students (5th Edition)

Given A circle has its center at the point (-2, 3). If one endpoint of a diameter is at (3, -5), To find out the other endpoint of the diameter. use theorem 10.1.2 As we know the center point divides the diameter into two halves i.e it is the mid point of the diameter. Midpoint M(xm,ym) =($\frac{x1+x2}{2}$ , $\frac{y1+y2}{2}$) (-2,3) =($\frac{3+x2}{2}$ , $\frac{-5+y2}{2}$) -2 =$\frac{3+x2}{2}$ ,3 =$\frac{-5+y2}{2}$ x2= -4 - 3 , y2 = 6 + 5 x2 = -7 , y2 = 11 The other point of the diameter (-7,11).