# Chapter 10 - Section 10.1 - The Rectangular Coordinate System - Exercises: 13a

C(4,$\frac{-5}{2}$)

#### Work Step by Step

Points A and B have symmetry with respect to point C. To find the coordinates of C given the points: A(3,-4) and B(5,-1) C is the mid point of A and B M=($\frac{x1+x2}{2}$, $\frac{y1+y2}{2}$) C = ($\frac{3+5}{2}$, $\frac{-4-1}{2}$) C(4,$\frac{-5}{2}$) Therefore the coordinates of B(4-a,6-b)

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