Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Appendix A - A.4 - Quadratic Equations - Exercises - Page 561: 38

Answer

$b = 8$

Work Step by Step

$a^{2} + b^{2} = c^{2}$ $(6)^{2} + b^{2} = (10)^{2}$ $36 + b^{2} = 100$ $b^{2} = 64$ $b = ±\sqrt {64}$ $b = ±8$ Since $b \ne -8$, the only answer is $b = 8$.
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