Answer
$x = \frac{-1+\sqrt {17}}{2}$ units.
Work Step by Step
$x \times (x+5) = (x+1) \times 4$
$x(x+5) = 4(x+1)$
$x^{2} + 5x = 4x + 4$
$x^{2} + 5x - 4x - 4 = 0$
$x^{2} + x - 4 = 0$
Use the quadratic formula to solve for $x$
$= \frac{-b±\sqrt {b^{2}-4ac}}{2a}$
$= \frac{-(1)±\sqrt {1^{2}-4(1)(-4)}}{2(1)}$
$= \frac{-1±\sqrt {1+16}}{2}$
$=\frac{-1±\sqrt {17}}{2}$
$x = 1.56, -2.56$
Since $x \ne - 2.56$, then $x = 1.56$ units.
$x = \frac{-1+\sqrt {17}}{2}$ units.
