Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter - Section 11.4 - Applications with Acute Triangles - Exercises - Page 529: 42

Answer

$90.2$ $ cm^{2}$

Work Step by Step

Using the formula given in the previous exercise, the area of the parallelogram is: $a \times b \times \sin \gamma$ $8 cm \times 12 cm \times \sin 70^{\circ}$$= 90.2$ $ cm^{2}$
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