Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter - Section 11.4 - Applications with Acute Triangles - Exercises - Page 529: 38

Answer

127.3

Work Step by Step

For the law of sines, we know that: $$\frac{a}{\sin \left(\alpha \right)}=\frac{b}{\sin \left(\beta \right)}=\frac{c}{\sin \left(\gamma \right)}$$ Thus, it follows: $$ a=\frac{90\sin \left(90^{\circ \:}\right)}{\sin \left(45^{\circ \:}\right)} \\ a=127.3$$
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