## Elementary Geometry for College Students (7th Edition)

$12\pi$
We first find the height of the circle: $h = \sqrt{8^2 - 4^2} = \sqrt{48} = 4\sqrt{3}$ Since this height is double the radius, we find: $r = 2 \sqrt{3}$ Thus, we find area: $A = \pi(2\sqrt{3})^2 = 12\pi$