Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 385: 45

Answer

15.7 ft/sec

Work Step by Step

Given The diameter of a carousel (merry-go-round) is 30 ft. At full speed, it makes a complete revolution in 6 s. We need to find out At what rate, in feet per second, is a horse on the outer edge moving Rate = $\frac{total distance traveled in one revolution}{time taken for one revolution}$ = $\frac{Perimeter o the circular path}{time taken to cover one revolution}$ = $\frac{2\pi r}{6}$ = $\frac{\pi d}{6}$ = $\frac{\pi * 30}{6}$ = 5$\pi$ = 15.7 ft/sec
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