# Chapter 6 - Section 6.1 - Circles and Related Segments and Angles - Exercises - Page 285: 11i

$m\angle 6=30^{\circ}$

#### Work Step by Step

In part e we determined that the $m\angle 2=120^{\circ}$. All radii of a circle are congruent, therefore $\overline{CQ}=\overline{BQ}$, creating an isosceles triangle. The two base angles of an isosceles triangle are congruent. So if we subtract the vertex angle ($\angle 2$) from $180^{\circ}$ and then divide the resulting number by two (two base angles), we will find the measure of the missing angle. $180-120=60\div2=30$ $m\angle 6=30^{\circ}$

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