#### Answer

$m\angle 4=10^{\circ}$

#### Work Step by Step

In part f we determined that the $m\angle 3=160^{\circ}$. All radii of a circle are congruent, therefore $\overline{CQ}=\overline{AQ}$, creating an isosceles triangle. The two base angles of an isosceles triangle are congruent. So if we subtract the vertex angle ($\angle 3$) from $180^{\circ}$ and then divide the resulting number by two (two base angles), we will find the measure of the missing angle.
$180-160=20\div2=10$
$m\angle 4=10^{\circ}$