Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.4 - The Pythagorean Theorem - Exercises - Page 252: 8a

Answer

$\overline{DE}=12$

Work Step by Step

Let $b = \overline{DE}$ $13^{2} = 5^{2}+ b^{2}$ Isolate $b$ $13^{2}-5^{2}=b^{2}$ $169-25=b^{2}$ $144=b^{2}$ Square root each side $12=b$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.