Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.4 - The Pythagorean Theorem - Exercises - Page 252: 8a



Work Step by Step

Let $b = \overline{DE}$ $13^{2} = 5^{2}+ b^{2}$ Isolate $b$ $13^{2}-5^{2}=b^{2}$ $169-25=b^{2}$ $144=b^{2}$ Square root each side $12=b$
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