Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.4 - The Pythagorean Theorem - Exercises - Page 252: 7a

Answer

$\overline{DF}=10$

Work Step by Step

$(\overline{DE})^{2}$ +$ (\overline{EF})^{2}$ = $(\overline{DF})^{2}$ $8^{2}$+$6^{2}=(\overline{DF})^{2}$ $64+36=(\overline{DF})^{2}$ $100=(\overline{DF})^{2}$ Square Root both sides $10=\overline{DF}$
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