Answer
The ideal viewing distance is about 10 feet.
Work Step by Step
We can find the ideal viewing distance $V$:
$D = 4.3~V$
$V = \frac{D}{4.3}$
$V = \frac{42}{4.3}$
$V \approx 10~ft $
The ideal viewing distance is about 10 feet.
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 236: 38
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