Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 236: 38

Answer

The ideal viewing distance is about 10 feet.

Work Step by Step

We can find the ideal viewing distance $V$: $D = 4.3~V$ $V = \frac{D}{4.3}$ $V = \frac{42}{4.3}$ $V \approx 10~ft $ The ideal viewing distance is about 10 feet.
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