Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 236: 25


Perimeter of $GHJKL=75$

Work Step by Step

Given pentagon $ABCDE\sim GHJKL$, side $AB$ corresponds to side $GH$. $\frac{AB}{GH}=\frac{6}{9}=\frac{2}{3}$ The ratio of the sides of the pentagons are 2:3. The ratio of the perimeters of the pentagons will also be 2:3. So... $\frac{2}{3}=\frac{50}{x}$ Cross Multiply... $2x=150$ Divide by 2... $x=75$ or The perimeter of $GHJKL=75$
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