Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 107: 38

Answer

m$\angle$CAB=57$^{\circ}$ m$\angle$CBA=33$^{\circ}$

Work Step by Step

m$\angle$C+m$\angle$CAB+m$\angle$CBA=180 90+24+x+x=180 2x=66 x=33$^{\circ}$ m$\angle$CBA=x=33$^{\circ}$ m$\angle$CAB=24+x=57$^{\circ}$
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