Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 105: 3

Answer

$m∠B$ = $46^{\circ}$

Work Step by Step

we know sum of all three angles of triangle is $180^{\circ}$ $m∠A+m∠B+m∠C$=$180^{\circ}$ $67^{\circ}+m\angle B+67^{\circ}$ = $180^{\circ}$ $m∠B$= $180^{\circ}−134^{\circ}$ $m∠B$ = $46^{\circ}$
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