Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 105: 1

Answer

$ 75^{\circ}$

Work Step by Step

we know sum of all three angles of triangle is $180^ {\circ}$ $m\angle A + m\angle B + m \angle C $= $180 ^ {\circ} $ $63^{\circ}+ 42^{\circ}+ \angle C$ =$ 180^{\circ}$ $105^{\circ}+\angle C$ = $180^{\circ}$ $ \angle C$ = $180^{\circ}-105^{\circ}$ $\angle C$ = $75^{\circ}$
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