Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 528: 25

Answer

x$\approx$ 10.5

Work Step by Step

using theorem 11.4.3 Law of cosine $x^{2}$ = $(8)^{2}$ + $(12)^{2}$ - 2*8*12*cos 60° $x^{2}$ = 64+144 - 2*8*12 * $\frac{1}{2}$ $x^{2}$ = 208 -96 $x^{2}$ = 112 x = $\sqrt 112$ x = 4$\sqrt 7$ $\approx$ 10.5 x$\approx$ 10.5
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