Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 528: 23

Answer

α = 50.7°

Work Step by Step

using theorem 11.4.3 Law of cosine cos α = $\frac{5^{2} + 9^{2} - 7^{2}}{2(5)(9)}$ cos α =$\frac{25 + 81 - 49}{90}$ cos α =0.6333 α = $cos^{-1}$(0.6333) α = 50.7°
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