#### Answer

$A = 6.77~in^2$

#### Work Step by Step

Since the measure of a base angle is $72^{\circ}$, we can let $\theta = 180^{\circ}-72^{\circ}-90^{\circ} = 18^{\circ}$
We can find the area of the triangle:
$A = s^2~sin~\theta~cos~\theta$
$A = (4.8~in)^2~sin~18^{\circ}~cos~18^{\circ}$
$A = 6.77~in^2$