Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.2 - The Cosine Ratio and Applications - Exercises - Page 512: 37

Answer

$55^{\circ}$

Work Step by Step

The length of a diagonal is $\sqrt{2}s$ Thus, we find: $tan(\alpha) = \frac{\sqrt{2}s}{s} \\ \alpha = tan^{-1}(\sqrt{2}) = 55^{\circ}$
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