Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.2 - The Cosine Ratio and Applications - Exercises - Page 511: 7

Answer

sin α = $\frac{a}{c}$ cos β = $\frac{a}{c}$ thus sin α = cos β

Work Step by Step

Lets take question 1 diagram: as we know sin α = $\frac{opposite}{hypotenus}$ for question 1 , sin α = $\frac{5}{13}$ cos β = $\frac{adjacent}{hypotenus}$ for question 1 , cos β = $\frac{5}{13}$ Therefore we can say that sin α = cos β = $\frac{5}{13}$
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