## Elementary Geometry for College Students (7th Edition) Clone

cos α = $\frac{sqrt of 2}{sqrt of 3}$ , cos β = $\frac{sqrt of 3}{sqrt of 5}$
Step 1: By Pythagoras theorem $(sqrt of 3)^{2}$ + $(sqrt of 2)^{2}$ = $c^{2}$ 3 + 2 = $c^{2}$ c = $\sqrt 5$ Step 2: cos α = $\frac{length of adjacent}{length of hypotenuse}$ cos α = $\frac{sqrt of 2}{sqrt of 3}$ Similarly cos β = $\frac{length of adjacent}{length of hypotenuse}$ cos β = $\frac{sqrt of 3}{sqrt of 5}$ Therefore cos α = $\frac{sqrt of 2}{sqrt of 3}$ , cos β = $\frac{sqrt of 3}{sqrt of 5}$