Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 10 - Section 10.5 - Equations of Lines - Exercises - Page 480: 41

Answer

$(\frac{a-c}{b}, a)$

Work Step by Step

$y=a$ $y=bx+c$ In this problem we want to equate the two expressions for y and solve for x, while treating a, b, and c as constants. $a=bx+c$ $a-c=bx$ $x=\frac{a-c}{b}$ Since it is given in the problem that $y=a$, our answer is $(\frac{a-c}{b}, a)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.