Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 10 - Section 10.5 - Equations of Lines - Exercises - Page 480: 39

Answer

(6, 0)

Work Step by Step

Equating the expressions for y: $\frac{1}{3}x-2=\frac{1}{2}x-3$ $1=\frac{1}{6}x$ $x=6$ Substituting $x=6$ into $y=\frac{1}{3}x-2$: $y=\frac{1}{3}*6-2$ $y=\frac{6}{3}-2$ $y=2-2$ $y=0$ So the answer is $(6, 0)$.
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