Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Appendix A - A.5 - The Quadratic Formula and Square Root Properties - Exercises - Page 562: 18

Answer

$a = 15$ $b = -2$ $c=-56$

Work Step by Step

A quadratic equation can be written in this form: $ax^2 + bx+c = 0$ where $a,b,$ and $c$ are real numbers and $a \neq 0$ We can use the quadratic formula to find the solutions of the equation: $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$ We can determine the values of $a, b,$ and $c$: $(3x+2)(5x-4) = 48$ $15x^2-2x-8 = 48$ $15x^2-2x-56 = 0$ $a = 15$ $b = -2$ $c=-56$
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