## Elementary Geometry for College Students (6th Edition)

$V=363.623$ m$^3$
The volume of a pyramid is: $V=\frac{1}{3}Bh$ So, $V=\frac{1}{3}100h$ To find h, substitute the slant height and half of the base's length into: $a^2+b^2=c^2$ In this case, we are solving for the leg of the triangle given that the hypotenuse is 12, and the other leg is 5. $a^2+5^2=12^2$ $a=10.90$ $V=\frac{1}{3}100(10.90)$ $V=363.623$ m$^3$