Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 9 - Section 9.2 - Pyramids, Area, and Volume - Exercises - Page 407: 23b


$V=705.18$ cm$^3$

Work Step by Step

Knowing the altitude of the pyramid, we can multiply it by the area of its base (acquired in part A), and one third in the equation: Volume of a Pyramid $= \frac{1}{3}Bh$ Altitude: $14.6$ cm Area of base (B): $144.9 $ cm$^2$ $V=\frac{1}{3}(144.9)(14.6)$ $V=705.18$ cm$^3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.