Answer
36$\pi$-72 in$^2$
Work Step by Step
A$_{sector}$=$\frac{90}{360}$($\pi$12$^2$)
A$_{sector}$=$\frac{1}{4}$(144$\pi$)
A$_{sector}$=36$\pi$
A$_{triangle}$=.5(12)(12)
A$_{triangle}$=72
A=36$\pi$-72
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 8 - Test - Page 388: 15
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