#### Answer

A=16$\pi$-32 in$^2$

#### Work Step by Step

d=s$\sqrt 2$
d=(4$\sqrt 2$)($\sqrt 2$)
d=8
r=.5d=4
A=$\pi$r$^2$-s$^2$
A=16$\pi$-32

Published by
Brooks Cole

ISBN 10:
9781285195698

ISBN 13:
978-1-28519-569-8

A=16$\pi$-32 in$^2$

d=s$\sqrt 2$
d=(4$\sqrt 2$)($\sqrt 2$)
d=8
r=.5d=4
A=$\pi$r$^2$-s$^2$
A=16$\pi$-32

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