Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 8 - Test - Page 388: 13

Answer

A=16$\pi$-32 in$^2$

Work Step by Step

d=s$\sqrt 2$ d=(4$\sqrt 2$)($\sqrt 2$) d=8 r=.5d=4 A=$\pi$r$^2$-s$^2$ A=16$\pi$-32
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