## Elementary Geometry for College Students (6th Edition)

$A(shaded) = 36 \pi - 54 \sqrt3$
Solving for the area of the circle is elementary: $A= \pi r^2 = 36 \pi$ We also know that the area of the hexagon is: $A = 3 \sqrt 3 /2(6^2)$ This gives: $A(shaded) = 36 \pi - 54 \sqrt3$